Cpp 移动构造函数的问题

这个是我的代码, 按照移动构造函数的定义, 我先创建了一个对象 a, 这个对象强制使用 move 调用移动构造函数赋值给 b, 这个时候, a, b 里面的成员变量的地址 data 应该是一样的, 为什么我这里显示的不一样?

运行结果

Constructor is called for 10 000000950D2FF7F8 // addr Move Constructor for 10 000000950D2FF818 // addr Destructor is called for 10 Destructor is called for nullptr

// C++ program with declaring the
// move constructor
#include <iostream>
#include <vector>
using namespace std;

// Move Class
class Move {

public:

    int* data;
    // Constructor
    Move(int d)
    {
        // Declare object in the heap
        data = new int;
        *data = d;
        cout << "Constructor is called for "
            << d << endl;
    };

    // Copy Constructor
    Move(const Move& source)
        : Move{ *source.data }
    {

        // Copying the data by making
        // deep copy
        cout << "Copy Constructor is called -"
            << "Deep copy for "
            << *source.data
            << endl;
    }

    // Move Constructor
    Move(Move&& source)
        : data{ source.data }
    {

        cout << "Move Constructor for "
            << *source.data << endl;
        source.data = nullptr;
    }


    // Destructor
    ~Move()
    {
        if (data != nullptr)

            // If pointer is not pointing
            // to nullptr
            cout << "Destructor is called for "
            << *data << endl;
        else

            // If pointer is pointing
            // to nullptr
            cout << "Destructor is called"
            << " for nullptr "
            << endl;

        // Free up the memory assigned to
        // The data member of the object
        delete data;
    }
};

// Driver Code
int main()
{
    // Vector of Move Class
    //vector<Move> vec;

    //// Inserting Object of Move Class
    //vec.push_back(Move{ 10 });
    //vec.push_back(Move{ 20 });
    Move a(10);
    cout << &(a.data) << endl;
    Move b = move(a);
    cout << &(b.data) << endl;
    return 0;
}