想找个邮件轮询和收发的可靠低成本方案

用 Python 写了个小工具：轮询收件箱，如果收到的邮件满足某个条件，则向 IFTTT 发送触发邮件。

目前运行在树莓派上，但是办公室有时候会断电。现在想找个可靠又低成本的服务来运行这个代码。我听有些服务器会疯掉邮件发送端口。想请问各位老哥，哪家服务比较好呢？

import time
import email
import imaplib
import smtplib, ssl
from email.mime.text import MIMEText
import base64
import os
from os.path import join, dirname
from dotenv import load_dotenv

dotenv_path = join(dirname(__file__), ".env")
load_dotenv(dotenv_path)
PASSWORD = os.environ["EMAIL_PASSWORD"]


def fire_in_the_hole():
    smtp_server = 'smtp.gmail.com'
    port = 465
    from_addr = '[email protected]'
    to_addrs = ['[email protected]']
    message = MIMEText('Hey big brother!')
    message['subject'] = 'Alert received'
    message['from'] = from_addr
    message['to'] = ', '.join(to_addrs)
    # we'll connect using SSL
    context = ssl.create_default_context()
    with smtplib.SMTP_SSL(smtp_server, port, context=context) as server:
        server.login(from_addr, PASSWORD)
        server.sendmail(from_addr, to_addrs, message.as_string())


def check_email():
    mail = imaplib.IMAP4_SSL('imap.gmail.com')
    mail.login('[email protected]', PASSWORD)
    mail.select('inbox')
    status, data = mail.search(None, 'UNSEEN', 'FROM "[email protected]"')
    mail_ids = []
    for block in data:
        mail_ids += block.split()
    if not mail_ids:
        return
    for i in mail_ids:
        status, data = mail.fetch(i, '(RFC822)')
        for response_part in data:
            if isinstance(response_part, tuple):
                message = email.message_from_bytes(response_part[1])
                if message.is_multipart():
                    mail_content = ''
                    for part in message.get_payload():
                        mail_content += part.get_payload()
                else:
                    mail_content = message.get_payload()
                mail_content = base64.b64decode(mail_content).decode('utf-8')
                if 'dropped' in mail_content:
                    fire_in_the_hole()


def task():
    while True:
        check_email()
        time.sleep(300)


if __name__ == "__main__":
    task()